1.95 kj of heat is required
to raise the temperature of
500 g of lead from 15°c to its final temperature. what is the final temperature if the specific heat capacity of lead is 130 j/(kg°c)?

45°C

We are given;

We are required to calculate the final temperature;

Q = mass,m × specific heat,c × Change in temperature,ΔT

ΔT = final temperature - initial temperature

We can rearrange the formula to calculate the change in temperature

ΔT = Q ÷  (m×c)

Therefore;

ΔT = 1950 J ÷ (0.5 kg × 130 J/Kg°C)

     = 30°C

But,

Final temperature = ΔT + Initial temperature

                              = 15°C + 30°C

                              = 45°C

Therefore, the final temperature is 45°C

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