Titanium and chlorine react to form titanium(iv) chloride, like this: ti(s) + 2 cl 2(g)-ticl 4( at a certain temperature, a chemist finds that a 7.0 l reaction vessel containing a mixture of titanium, chlorine, and titanium(iv) chloride at equilibrium has the following composition compound amount 1.67 g cl 2.93 g tici 2.02 g ti calculate the value of the equilibrium constant k for this reaction. round your answer to 2 significant digits.

The value of equilibrium constant for the reaction is

Explanation:

The given chemical equation follows:

The expression of for the above reaction follows:

Concentration of pure solids and liquids are taken as 1 in the equilibrium constant expression.

Thus, titanium and titanium tetrachloride does not appear in the expression.

We are given:

Equilibrium amount of titanium = 2.93 g

Equilibrium amount of titanium tetrachloride = 2.02 g

Equilibrium amount of chlorine gas = 1.67 g

To calculate the number of moles, we use the equation:

Given mass of chlorine gas = 1.67 g

Molar mass of chlorine gas = 71 g/mol

Putting values in above equation, we get:

Volume of vessel = 7.0 L

Concentration of a substance is calculated by:

So, concentration of chlorine gas =

Putting the value in equilibrium constant expression, we get:

Hence, the value of equilibrium constant for the reaction is