Ahot iron ball is dropped into a 200. g sample of water initially at 50°c. if 8.4 kj of heat is transferred from the ball to the water, what is the final temperature of the water? (the specific heat of water is 4.2 j/(g·°c).

The final temperature of water is 60°C

Explanation:

To calculate the final temperature of water, we use the equation:

where,

q = amount of heat absorbed = 8.4 kJ = 8400 J  (Conversion factor:  1 kJ = 1000 J)

m = mass of water = 200 g

c = specific heat capacity of water = 4.2 J/g.°C

= change in temperature =

Putting values in above equation, we get:

Hence, the final temperature of water is 60°C