A transportation worker takes a simple random sample of 105 toll booth receipts for one day and finds that the mean is $9.45 with a standard deviation of $2.41. What is the 99% confidence interval for the mean amount of all the receipts that day?

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

6mm^3 or .6cm^3

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  36     6

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6     6   6

factor trees are nice.