Find the original concentration of a solution diluted from 15.00 ml to 125.0 ml with a final concentration of 0.00383 m

0.03192 M

Explanation:

We are given;

Initial volume before dilution, V1 = 15.0 mL or 0.015 LVolume after dilution, V2 = 125.0 mL or 0.125 LConcentration after dilution, M2 = 0.00383 M

We are required to calculate the initial concentration, M1 before dilution.

To answer the question, we will use the dilution formula;Dilution formula is given by; M1V1 = M2V2

Rearranging the formula;

M1 = M2V2 ÷ V1

    = ( 0.00383 M × 0.125 L) ÷ 0.015 L

   = 0.03192 M

Therefore, the original concentration of the solution before dilution is 0.03192 M

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic