Sodium (na) and iodine gas (i2) react to form sodium iodine (nai) .

which equation is a correct representation of the balanced equation?

nai→2na+i2

na→nai+i2

2na+i2→2nai

i2→2nai+2na

2Na +  I₂  → 2NaI

Explanation:

The sodium and iodine gas react to form the sodium iodine, correct chemical equation is given below:

2Na +  I₂  → 2NaI

All other equations are incorrect because,

NaI → 2Na + I₂

In this equation sodium iodine split to gives sodium and iodine.

Na  → NaI + I₂

This equation is incorrect because just one element sodium produces sodium iodine and iodine which is impossible.

I₂  →  2NaI + 2Na

This equation is also incorrect because just one element iodine produces sodium iodine and iodine which is impossible, because if there is no sodium atom present in reactant side then it would not appear in product.

i am going to put the answers in order i dint feel like typing it out so yeah

a

d

c

b

b

b

a

d

a

b

c

c

c

b

d

14,16 18 reacts with group