150 kg of wood with 11% moisture enters the dryer. 12.3 kg of water come out.
a) calculate the dry wood output percentages.

weight % of water in dry wood come output  = 3.05 %

and weight % of wood in dry wood come output = 96.95 %

Explanation:

given data

mass of wood = 150 kg

moisture = 11%

water come out = 12.3 kg

to find out

dry wood output percentages

solution

we know that moisture in wet wood is = 11% = 11%of 150

moisture in wet wood = 16.5 kg

wood in wet wood = mass of wet wood - moisture in wet wood

= 150 - 16.5

= 133.5 kg

so

water mass balance will be here

water in wet wood = water remove + water in dry wood

16.5 = 12.3 + water in dry wood

water in dry wood = 4.2 kg

and

wood mass balance is here

wood in wet wood = wood in water remove + wood in dry wood

133.5 = 0 + wood in dry wood

wood in dry wood = 133.5 kg

so we can say

dry wood contain here

wood = 133.5 kg

water = 4.2 kg

so total is = 137.7 kg

so

weight % of water in dry wood come output = = 3.05 %

and weight % of wood in dry wood come output =   = 96.95 %

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pleaze mark brainliest!

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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