Lithium and nitrogen react to produce lithium nitride: 6li + n2 --> 2li3n how many moles of n2 are needed to react with 0.500 mol of lithium?

The number of moles of that is required for reacting with the  0.500 mol of Lithium is 0.0833 moles.

6 moles → 1 moleN_2

0.500 mol → X

So,

0.500 × 1  = 6x

x = 0.0833 moles

Therefore we can conclude that the number of moles of that is required for reacting with the  0.500 mol of Lithium is 0.0833 moles.

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Explanation:

             6Li + N₂ ⟶ 2Li₃N

n/mol  0.500  

1 mol of N₂ reacts with 6 mol of Li

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