The complete combustion of octane, c8h18, a component of gasoline, proceeds as follows: 2c8h18(l)+25o2(g)→16co2(g)+18h2o(g) relevant volumetric equivalencies 1 gal = 3.785 l 1 l = 1000 ml
part a how many moles of o2 are needed to burn 1.35 mol of c8h18?

Moles of oxygen needed to burn given amount of octane is 16.875 moles.

Explanation:

We are given:

Moles of octane burned = 1.35 mol

For the given chemical reaction:

By Stoichiometry of the reaction:

When 2 moles of octane is burnt, then 25 moles of oxygen are needed

So, when 1.35 moles of octane is burned, then = of oxygen are needed.

Hence, moles of oxygen needed to burn given amount of octane is 16.875 moles.

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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