During an experiment, 95 grams of calcium carbonate reacted with an excess amount of hydrochloric acid. if the percent yield of the reaction was 82.15%, what was the actual amount of calcium chloride formed? caco3 + hcl → cacl2 + co2 + h2o 105.3 grams 101.1 grams 95.6 grams 86.5 grams

Actual yield: 86.5 grams.

Explanation:

How many moles of formula units in 95 grams of calcium carbonate ?

Refer to a modern periodic table for relative atomic mass data:

Formula mass of :

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How many moles of will be produced?

The coefficient in front of in the chemical equation is the same as that in front of . That is:

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What's the theoretical yield of calcium chloride? In other words, what's the mass of of ?

Again, refer to a periodic table for relative atomic data:

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What's the actual yield of calcium chloride?

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you need to give more information

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.