Calorimetry can be used to find heats of combustion. suppose a calorimeter someone to determine that 4032 kj of heat is released during the combustion of 88.0 grams of propane, c3h8 (44.0 g/mol). what would be the amount of heat released for the combustion of 0.500 moles of propane?

1008.0 kJ.

Explanation:

n = mass/molar mass = (88.0 g)(/(44.0 g/mol) = 2.0 mol.

∴ The combustion of 2.0 moles of propane produces 4032.0 kJ.

Using cross multiplication:

The combustion of 2.0 moles of propane produces → 4032.0 kJ.

The combustion of 0.5 moles of propane produces → ??? kJ.

∴ The amount of heat released for the combustion of 0.5 moles of propane = (4032.0 kJ)(0.5 mol)/(2.0 mol) = 1008.0 kJ.

particle   p is an electron and particle q is a neutron

answer is: naturally occurring solid, inorganic compound or element is mineral.

minerals usually have crystalline form, that means than crystal constituents (atoms, molecules or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

for example magnetite is a mineral of iron oxide (fe₂o₃).

calcite is a carbonate mineral and the most stable polymorph of calcium carbonate (caco₃).

dolomite is an   carbonate mineral composed of calcium magnesium carbonate (camg(co₃)₂).