John is building a custom wall for a kitchen remodel. he knows the space for the wall is square with an area of 121 feet. how long does his diagonal brace need to be?

His diagonal brace need to be 15.55 feet long in the kitchen.

Step-by-step explanation:

Given : The wall of the kitchen is in the shape of a square.

Area of the wall = 121 sq ft

Let us assume the each side of  wall = a ft

Now, AREA OF THE SQUARE = Side x Side

⇒   a x  a = 121 sq units

So, each side of the  kitchen wall is 11 ft.

Now,as  we know in a square : EACH ANGLE IN THE  SQUIRE IS A RIGHT ANGLE.

So, by Pythagoras Theorem, Diagonal D is:

Hence,  his diagonal brace need to be 15.55 ft long in the kitchen.

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

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