Will give brainiest 1. 3.0 l of a gas is at a temperature of 78oc. find the volume of the gas at standard temperature. 2. at what temperature (in oc) would the volume of a gas be equal to 45.7 l, if the volume of that gas was 33.9 l at 12.4oc?

1. 2.33 L.

2. 111.74 °C.

Explanation:

1. 3.0 L of a gas is at a temperature of 78°C. Find the volume of the gas at standard temperature.

V ∝ T.

∴ V₁T₂ = V₂T₁.

V₁ = 3.0 L, T₁ = 78°C + 273 = 351 K.

Standard temperature = 0.0 °C.

V₂ = ??? L, T₂ = 0.0 °C + 273 = 273 K.

∴ V₂ = V₁T₂/T₁ = (3.0 L)(273 K)/(351 K) = 2.33 L.

2. At what temperature (in oC) would the volume of a gas be equal to 45.7 L, if the volume of that gas was 33.9 L at 12.4oC?

∵ V₁T₂ = V₂T₁.

V₁ = 33.9 L, T₁ = 12.4°C + 273 = 285.4 K.

V₂ = 45.7 L, T₂ = ??? K.

∴ T₂ = V₂T₁/V₁ = (45.7 L)(285.4 K)/(33.9 L) = 384.74 K.

∵ T(K) = T(°C) + 273.

∴ 384.74 K = T(°C) + 273.

∴ T(°C) = 384.74 K - 273 = 111.74 °C.

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)