65 ml of a 1.3 m solution is dilluted to a total volume of 208 ml. a 104 ml portion of that solution is dilluted by adding 109 ml of water. what is the concentration? assume the volumes are additive

65ml x 1.3 molar = 0.0845 moles solution #1

0.0845 moles / .208 L = 0.4 M

0.4M × 104 ml / 213 ml = .20 M after sig figs

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na