A body rolls over a horizontal, smooth surface without slipping with a translational kinetic energy E. Show that the kinetic energy of the body is E=(1+K 2 /R 2 )
where K is the radius of gyration and R is the radius of the body. Using the above relation, find the
total kinetic energy of a circular disc.
b) A wheel of mass 1000 kg and radius 1 m is rotating at the rate of 420 r. p.m. What is the
constant torque required to stop the wheel in 14 rotations, assuming the mass to be
concentrated at the rim of the wheel?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

i think the answer is tomato juice? not entirely sure though