Chemistry, 14.07.2019 17:30 kiwi6316

If the ph of a solution is 3.9 what would the poh be

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To determine the pOH Of solution we can use the pka value for the ionization constant of water at 25 degrees Celsius to solve this the relationship would be as follows.

PH + POH = 14

3.9 + x = 14

POH = 14 - 3.9 = 11 - 0.9 = 10.1

The POH would be 10.1.

Answer from: gstinson98

pOH of the solution will be 10.1

Explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration present in a solution. The equation used to represent pOH of the solution follows:

$pOH=-\log[OH^-]$

We are given:

pH of the solution = 3.9

To calculate the pOH os the solution, we use the following equation:

pH+pOH=14

Putting values in above equation, we get:

$3.9+pOH=14\\\\pOH=10.1$

Hence, pOH of the solution will be 10.1

Answer from: Quest

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Answer from: Quest

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

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