In a hypothetical population of 1000 frogs there exists a gene, d, with two alleles (d and d). 280 of the frogs are homozygous dominant (dd), and 220 are homozygous recessive (dd). what is the frequency of heterozygotes in the population?

The frequency of heterozygotes is 0.5

Explanation:

The frequency of heterozygotes can be get from the Weinberg equation:

p + q = 1

The number of individuals = 1000

The frequencies of dominant (DD) = q = 280/1000 = 0.28

The frequencies of recessive (dd) = p = 220/1000 = 0.22

The frequency of heterozygotes is equal to:

q + p = 0.28 + 0.22 = 0.5

solvent

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