The locus B on the X chromosome of a malaria-carrying mosquito shows a 49% recombination rate with respect to the locus M. Since a recombination rate of 50% is essentially indistinguishable from independent assortment, you might be tempted to look for a locus that falls between B and M. Before you decide to do all that work, you run a chi square test to determine the P value of your experiment. Required:
What range of P values would tell you that you should accept the conclusion that locus B and locus M are, indeed, 49mu apart and that another locus is not necessary?

The correct answer is - P = 0.45

Explanation:

The Chi-square test is a test that determines the assorted genes independently. Here p-values used to make conclusions in significance testing.

If the p value is less than the significance level we expect or choose, then this null hypothesis is rejected in favor of the alternative hypothesis. It p value is greater than or equal to the significance level, then we fail to reject the null hypothesis.

So in this case, as the recombination rate is 49% so the p value which satisfies the conclusion will be around 0.45 and values near to it.

the overall balanced equation

6co2 + 6h2o > c6h12o6 + 6o2

sunlight energy

where: co2 = carbon dioxide

h2o = water

light energy is required

c6h12o6 = glucose

o2 = oxygen