Biology, 23.03.2021 16:20 tayler4766

En las plantas de guisante la forma lisa de la vaina (cubierta) es dominante sobre la forma rugosa. Se cruzan plantas de vaina lisa con plantas de vaina rugosa, ambas homocigotas. Determine fenotipo y genotipo de F1 y F2.Resultante

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Answer from: kyasnead8189

F1)

Genotipo: 100% Heterocigota, LlFenotipo: 100% Frutos de vaina lisa

F2)

Genotipo: 25% Homocigota dominante, LL

50% Heterocigota, Ll

25% Homocigota recesivo, ll

Fenotipo: 75% Frutos de vaina lisa (LL + Ll)

25% frutos de vaina rugosa (ll)

Explanation:

Datos disponibles:

Vaina lisa es la característica dominanteVaina rugosa es la característica recesivaEl gen que codifica la textura de la vaina es dialélicoLlamemos L al alelo dominante que expresa vaina lisa, y l al alelo recesivo que expresa vaina rugosa

1er Cruza: planta de vaina lisa homocigota x planta de vaina rugosa homocigota

Parentales) LL x ll

Fenotipo) Lisa Rugosa

Gametos) L L l l

Cuadro de Punnett) L L

l Ll Ll

F1) 4/4 = 100% de la progenie será heterocigota, Ll, para la textura de vaina, pero expresarán vainas lisas.

2da Cruza: Dos plantas provenientes de la F1

Parentales) Ll x Ll

Fenotipo) Liso Liso

Gametos) L l L l

Cuadro de Punnett) L l

L LL Ll

l Ll ll

F2) 1/4 = 25% de la progenie será homocigota dominante, LL

2/4 = 50% de la progenie será heterocigota, Ll

1/4 = 25% de la progenie será homocigota recesiva, ll

3/4 = 75% de la progenie tendrá vainas lisas

1/4 = 25% de la progenie tendrá vainas rugosas.

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