Write the equation of a hyperbola with vertices (0, -2) and (0, 2) and co-vertices (-4, 0) and (4, 0).
y squared/16 minus x squared/4 equals 1
x squared/4 minus y squared/16 equals 1
y squared/4 minus x squared/16 equals 1
x squared divided by 16 minus y squared divided by 4 equals 1

C. y squared/4 minus x squared/16 equals 1

Step-by-step explanation:

Given that vertices of hyperbola are (0,-2) and (0,2)  and

Co-vertices of hyperbola as (-4,0) and (4,0)  then a sketch will show you that this hyperbola has its transverse axis on the y-axis and has its center at the origin (0,0)

This means that the standard equation for the hyperbola should follow;

Using the coordinates of the vertices, you can find the length of the transverse axis and the value of a as;

(0,-2) and (0,2) , 2--2=4

2a=4

a=4/2=2

a=2

Using the coordinates of the co-vertices, you can find the length of the conjugate axis as;

(-4,0) and (4,0) ⇒ 4--4=8

2b=8

b=8/2=4

b=4

substitute values in equation as;

walter needs to make at least 5 more cookies but no more than 40. 5 ≥ x ≥ 40;

step-by-step explanation:

walter has to make a minimum of 20 cookies. he already has 15 cookies made, so he must make 5 more to meet the minimum.

the maximum amount of cookies he can make is 55. he already has 15, so he has to make no more than 40 more cookies to meet the maximum.

so then what are you asking?

step-by-step explanation: