In rabbits, black fur (B) is dominant over gray fur (b). If an individual that is heterozygous for fur color is crossed with a gray individual, what is the probability that they will have a dominant phenotype?

1/2 or 50%

Explanation:

Black fur (B) is dominant while gray fur (b) is recessive.

The heterozygous individual would have the genotype Bb

The gray individual would the genotype bb.

       Bb    x    bb

    Bb   Bb   bb   bb

1/2 Bb - Black fur

1/2 bb - Gray fur

The dominant phenotype is black fur. Therefore, the probability of the progeny having a dominant phenotype is 1/2 or 50%.

answer by yourhope:

hi! : )

in which structure in the nucleus are ribosomes made?

b) nucleolus!

: )