Advanced Placement (AP), 11.11.2020 19:50 ummsumaiyah3583

The trade networks described by the two sources were most strongly influenced by:

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Answer from: azaz1819

There are different kinds of trade. The trade networks described by the two sources were most strongly influenced by Increased European demand for luxury goods.

What are trade networks A Trade network is known as the different kinds of roads, routes or paths by which trade can be seen.

The Demand for luxury goods often goes up when the wealth or income of a person increases and thus did influence the trade routes that were taken by people.

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The trade networks described by the two sources were most strongly influenced by

(1 point)

Increased Asian demand for food imports.

Increased European demand for luxury goods.

Increased Chinese maritime activity in the Indian Ocean.

Increased demand for precious metals within European colonies in the Americas.

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Answer from: ianim207

The correct answer to this open question is the following.

Unfortunately, your question is incomplete. You did not include the description of the trade networks or the sources. Without that information, we do not know what you are talking about.

However, trying to help you with something, we can comment on the following example.

We can refer to the trade networks developed in the Trans-Saharan

trade. These traders were merchants of the African region -North and Western Africa- who traveled in caravans, using the camel to transport people and products across the deathly Sahara Desert.

They traded many products such as salt and gold, which were the most precious resources of the time. Gold was a valuable mineral with high value, and salt was as important to preserve food. But they also traded animal skins, ivory, silver, sugar, pepper, and slaves, to important trade centers such as Timbuktu and Djenne.

Answer from: Quest

correct answer for apex users would be /opportunities for growth/

Answer from: Quest

The answer is (d) 7/2======we have $f(x) = \begin{cases} x & \text{ for } x \le 0 \\ x + 1 & \text{ for } x \ \textgreater \ 0 \end{cases}$ we also have an integral $\displaystyle\int_{-2}^1 x\, f(x)\; dx$ notice how function f splits up at x = 0. there's a left piece and a right pieceso we'll need to do the same thing with our integral: split it at x = 0we use a property of integrals that allows us to split up and sum: $\displaystyle\int_{-2}^1 x\, f(x)\; dx = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx$ notice that for the piecewise function f, the function has the equationf(x) = x when x ≤ 0. so for the integral $\int_{-2}^0 x\, f(x)\; dx$ , f(x) = x so it changes into $\begin{aligned} \int_{-2}^0 x\, f(x)\; dx & = \int_{-2}^0 x \cdot x\; dx \\ & = \int_{-2}^0 x^2\; dx \\ & = \left[\frac{x^3}{3}\right]_{-2}^0 & & \text{\footnotesize antidifferentiate} \\ & = 0 - \frac{(-2)^3}{3} \\ & = \frac{8}{3} \end{aligned}$ for the piecewise function f, the function has the equationf(x) = x+1 when x > 0. for the integral $\int_{0}^1 x\, f(x)\; dx$ , we have $\begin{aligned} \int_{0}^1 x\, f(x)\; dx & = \int_{0}^1 x(x+1)\; dx \\ & = \int_{0}^1 (x^2+x)\; dx \\ & = \left[ \frac{x^3}{3} + \frac{x^2}{2}\right]_0^1 \\ & = \frac{1}{3} + \frac{1}{2} - 0 = \frac{5}{6} \end{aligned}$ therefore, back to our splitted integral: $\begin{aligned} \displaystyle\int_{-2}^1 x\, f(x)\; dx & = \displaystyle\int_{-2}^0 x\, f(x)\; dx + \displaystyle\int_{0}^1 x\, f(x)\; dx \\ & = \frac{8}{3} + \frac{5}{6} \\ & = \frac{7}{2} \end{aligned}$
Can anyone me on this ap calc question? ?

Can anyone me on this ap calc question? ?

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