2 + 2-5-6+7++7+8+9-64​

55

Explanation:

Sum(from K = 1 to N) of K = Total(N) = T(N)

T(N) = 1 + 2 + 3 + … + N

Subtract one from each of N terms.

T(N) = N + (0 + 1 + 2 + … + (N - 1))

T(N) = N + T(N - 1)

Explicitly writing out T(N - 1) in the previous form. This is the same as 1 + 2 + … + 9.

T(N) = N + (1 + 2 + 3 + … + (N - 1))

Subtract one from each of N - 1 terms.

T(N) = N + (N - 1) + (0 + 1 + 2 + … + (N - 2))

T(N) = N + (N - 1) + T(N - 2)

Subtract one from each of N - 2 terms.

T(N) = N + (N - 1) + (N - 2) + T(N - 3)

T(N) = N + (N - 1) + (N - 2) + … + (N - N)

Rewriting without parenthesis.

T(N) = N + N - 1 + N - 2 + … + N - N

Now rearrange the terms so it's all N's at the beginning and all other numbers after.

T(N) = N * N - (1 + 2 + ... + (N - 1))

To give a concrete example with T(4):

T(4) = 4 + (4 - 1) + (4 - 2) + (4 - 3) + (4 - 4)

T(4) = 4 + 4 - 1 + 4 - 2 + 4 - 3 + 4 - 4

T(4) = 4 + 4 + 4 + 4 + 4 - 4 - 1 - 2 - 3

Cancelling out the - 4 with a + 4.

T(4) = 4 + 4 + 4 + 4 - 1 - 2 - 3

T(4) = (4 + 4 + 4 + 4) - (1 + 2 + 3)

Divide the left term by four.

T(4) = 4 * (1 + 1 + 1 + 1) - (1 + 2 + 3)

T(4) = 4 * (4) - (1 + 2 + 3)

Another concrete example with T(5):

T(5) = 5 + (5 - 1) + (5 - 2) + (5 - 3) + (5 - 4) + (5 - 5)

T(5) = 5 + 5 - 1 + 5 - 2 + 5 - 3 + 5 - 4 + 5 - 5

T(5) = 5 + 5 + 5 + 5 + 5 + 5 - 5 - 1 - 2 - 3 - 4

Cancelling out the -5 with a + 5.

T(5) = 5 + 5 + 5 + 5 + 5 - 1 - 2 - 3 - 4

T(5) = (5 + 5 + 5 + 5 + 5) - (1 + 2 + 3 + 4)

Divide the left term by five.

T(5) = 5 * (1 + 1 + 1 + 1 + 1) - (1 + 2 + 3 + 4)

T(5) = 5 * (5) - (1 + 2 + 3 + 4)

Back to our original example:

T(N) = N * N - (1 + 2 + ... + (N - 1))

T(N) = N * N - (T(N - 1))

This next bit is very important. We already know from above that T(N) = N + T(N - 1). So we're going to subtract N to from sides of the equation.

T(N) - N = N * N - T(N - 1) - N

Adding parenthesis for clarity. Note that when we bring the - N at the end inside the parenthesis the sign changes.

T(N) - N = N * N - (T(N - 1) + N)

Reordering the last term for clarity.

T(N) - N = N * N - (N + T(N - 1))

Then we replace (N + T(N - 1)) with T(N).

T(N) - N = N * N - (T(N))

Removing parenthesis for clarity.

T(N) - N = N * N - T(N)

Add T(N) to both sides of the equation.

T(N) - N + T(N) = N * N - T(N) + T(N)

Reorder the left side and cancel the T(N) terms on the right side.

T(N) + T(N) - N = N * N

2 * T(N) - N = N * N

Add N to both sides.

2 * T(N) = N * N + N

Divide both sides by two.

T(N) = (N * N + N) / 2

A couple ways to rewrite the same thing.

T(N) = (N^2 + N) / 2

T(N) = (N * (N + 1)) / 2

So for your original question:

T(10) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

We know that T(N) = (N^2 + N) / 2

T(10) = (10^2 + 10) / 2

T(10) = (100 + 10) / 2

T(10) = (110) / 2

T(10) = 55

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y ahora me estoy dando cuenta

los primos de carlos y lisa son beatriz y sofia.