determine the force of gravitational attraction between a 78kg boy sitting 2 meters away from a 65kg girl.

F = 8.45 * 10^-8 N

Explanation:

The gravitational force is calculated using

F = GMm/r²

Where

G represent gravitational constant = 6.67 * 10^(-11)

M = Mass of the boy = 78kg

m = Mass of the girl = 65kg

r = Distance between them = 2m

Substitute these values in the formula, we have:

F = (6.67 * 10^(-11) * 78 * 65)/2²

F = (6.67 * 78 * 65 * 10^(-11))/4

F = (33816.9 * 10^(-11))/(4)

[Divide by the denominator]

F = 8454.225 *10^(-11)

[Expand]

F = 8.454225 * 10³ * 10^(-11)

F = 8.454225 * 10^(3-11)

F = 8.454225 * 10^-8

[Approximate]

F = 8.45 * 10^-8 N

Hence, the force of attraction between them is 8.45 * 10^-8 N

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answer; i believe the correct answer is norming;