What is the center of a circle represented by the equation (x=9)2+(y-6)2=10??
O (-96)
O (-6.9)
0 (6-8)

The center is (9, 6)

Explanation:

We are given the equation;

(x-9)²+(y-6)²=10

We are required to calculate the center of a circle.

To answer the question we need to know that;

When an equation of a circle is written in the form,

(x-a)² + (y-b)² = r²

(a,b) is the center of the circle while r is the radius

Thus, in this case, from the equation;

(x-9)²+(y-6)²=10

The center is (9, 6) and the radius is 3.162 units

well this isn't a question but if you are asking if it is true or false it is, true.