A violin string has a length of 0.45 m it it turned to a frequency of 392 Hz. if the violinist wants to play a note with frequencyy of 440 hz where should she place her finger?

0.05 m from the top end

Explanation:

Data provided in the question:

Length of the violin string, λ₁ = 0.45 m

Frequency, f₁ = 392 Hz

New frequency of the violin note, f₂ = 440 Hz

Now,

The velocity of the wave in the string remains constant constant if tension remains constant.

Also,

velocity, v = fλ

thus,

f₁λ₁ = f₂λ₂

392 × 0.45 = 440 × λ₂

or

λ₂ = 0.40 m

thus,

The finger should be placed at (0.45 - 0.40 ) = 0.05 m from the top end

answer; education;

answer; role- taking;