Suppose we have a 12.2-l sample containing 0.50 mol oxygen gas (o2) at a pressure of 1 atm and a temperature of 25oc. if all this o2 were converted to ozone (o3) at the same temperature and pressure, what would be the volume of the ozone

f all this O₂ were converted to ozone (O₃) at the same temperature and pressure, the volume of the ozone will be:

8.1 L

Explanation:

The Avogadro Law states that:

V₁ / n₁ = V₂ / n₂ (1)

Given that:

V₁ = 12.2 L

V₂ = ?

n₁ = 0.5 mol

n₂ = ?

The chemical equation of the conversion is as follow:

3  O₂  ⇒ 2 O₃

so putting the values in the above equation no. 1

12.2 / 3 = V₂ / 2

V₂ = (12.2 x 2) / 3

V₂ = 8.1 L

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