A gas that has a volume of 28 liters, a temperature of 450c, and an unknown pressure has its volume increased to 34 liters and its temperature decreased to 350c. If i measure the pressure after the change to be 2. 0 atm, what was the original pressure of the gas?.

2.82 atm

Explanation:

Initial:

V1 = 28 liters, T1 = 450 C = 450 + 273 K = 723 K, P1 = ?

Final:

V2 = 34 liters, T2 = 350 C = 350 + 273 K = 623 K, P2 = 2.0 atm

Use P1 * V1 / T1 = P2 * V2 / T2

so P1 = P2 * (V2/V1) * (T1/T2) = 2.0 * (34/28) * (723/623) = 2.82 atm

the answer is:

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