Calculate the quantity of o₂ would be required to generate 13. 0 mol of no₂ in the reaction below assuming the reaction has only 80. 0% yield. 2 no (g) + o₂ (g) → 2 no₂ (g).

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The answer is : v = 55 + 8m plug in m = 25 v = 55 + 8(25) = 255 25 minutes after baxter begins filling the tank, the volume of water in the tank will be 255 gallons. slope: m = 8 gal/min for every min the water is on, the volume of water in the tank increases by 55 gallons. y-intercept: 55 (0,55) the initial volume of water in the tank was 55 gallons.