For the following reaction, kc = 15 at 700 k. 2 no(g) + cl2(g) ⇄ 2 nocl(g) if we have [no] = 0. 15 m, [cl2] = 0. 15 m, [nocl] = 0. 40 m at 700 k, what will happen?.

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answer:

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explanation:

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