Calculate δh°f in kj/mol for benzene, c6h6, from the following data: 2c6h6(l) + 15o2(g) → 12co2(g) + 6h2o(l); δh° = -6534 kj δh°f(co2) = -393. 5 kj/mol; δh°f(h2o) = -285. 8 kj/mol.

the answer to the question is "five to eight weeks after the test date"

answer:

142.925

explanation:

6 x 19 = 114

114 x 84 = 9,576

9,576 ÷ 67 = 142.925 and so on many numbers.

hope it !