0= (2y-1) (8-y) Let the y = u and y = d be unique solutions to the equation above. What is the value of u ⋅ d?

 The value of u · d = 4

Explanation:  

(2y -1) = 0 , 2y = 1  ,  y = 1/2 .  u = 1/2

(8-y)=0  y = 8  d = 8

Substitute values for u·d   1/2 · 8 = 4

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