Answers: 3
![E[X]=\displaystyle\sum_xx\,P(x)=0\cdot0.125+1\cdot0.428+\cdots+4\cdot0.083](/tpl/images/0597/1074/dc778.png)
![E[X]=1.596](/tpl/images/0597/1074/990fa.png)
![E[X^2]=\displaystyle\sum_xx^2\,P(x)=0^2\cdot0.125+1^2\cdot0.428+\cdots+4^2\cdot0.083](/tpl/images/0597/1074/cd47f.png)
![E[X^2]=3.752](/tpl/images/0597/1074/7604b.png)
is![V[X]=E[(X-E[X])^2]=E[X^2-2X\,E[X]+E[X]^2]=E[X^2]-E[X]^2](/tpl/images/0597/1074/8b0ab.png)
![V[X]=2.156](/tpl/images/0597/1074/b1d15.png)
![\sqrt{V[X]}\approx\boxed{1.468}](/tpl/images/0597/1074/9efc8.png)
Another question on SAT
SAT, 24.06.2019 08:30
What kinds of antigens are found on the rbcs of a person with a+ blood
Answers: 3
SAT, 26.06.2019 21:40
Consider a normal distribution of frog weights with u = 500 grams and o = 65 grams. a sample of size 2,000 is drawn from this population. approximately how many of the 2,000 cases would you expect to find between 435 and 565?
Answers: 3
You know the right answer?
From the probability distribution, find the standard deviation for the random variable x, which repr...
Questions
Mathematics, 14.03.2022 06:10
Geography, 14.03.2022 06:10
Mathematics, 14.03.2022 06:20
Mathematics, 14.03.2022 06:20
Chemistry, 14.03.2022 06:20
Mathematics, 14.03.2022 06:20
Computers and Technology, 14.03.2022 06:20
