Physics, 23.07.2019 00:30 Anum3834

An object has an altitude of 2 times the earth's radius, re and experiences some force of gravity, f. if the object's altitude is doubled, then the new force of gravity will be

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Note: I assume the altitude is measured from Earth's center (it's not clear from the text if it's from the Earth's center or from the surface)

The force of gravity experienced by the object is given by
$F=G \frac{Mm}{r^2}$
where
G is the gravitational constant
M is the mass of the Earth
m is the mass of the object
r is the distance of the object from Earth's center

Initially, its distance from Earth's center is twice the Earth radius: r=2 r_e

, so the force of gravity is
$F=G \frac{Mm}{(2r_e)^2}=G \frac{Mm}{4 r_e^2}$

Later, the object altitude is doubled, so its new distance from Earth's center is 4 times the Earth's radius:
r'=4 r_e

and so the new force of gravity is
$F'=G \frac{Mm}{(4 r_e)^2}=G \frac{Mm}{16 r_e^2}= \frac{1}{4} G \frac{Mm}{4 r_e^2} = \frac{1}{4}F$
therefore, the new force is 1/4 of the original force.

Answer from: Quest

It won't lose or gain electrons if it's a covalent bond it shares the electrons with another atom or atoms. if it is an ionic bond it will lose the 3 electrons on the outer shell and become a positively charged ion. credit goes to @sunshinebaby of answers.yahoo.com.

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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