How much heat is needed to vaporize 33.3 grams of ethyl alcohol at its boiling point of 78.0°c? the latent heat of vaporization of ethyl alcohol is 857 j/g. round your answer to three significant figures. joules

Q = 28538.1 J

Explanation:

As we know that heat require to vaporize the ethyl alcohol is given as

Q = mL

here we know that

m = mass = 33.3 gram

L = latent heat of fusion = 857 J/g

now from above formula

so heat required in three significant figures is given as

so heat required to vaporize ethyl alcohol is

answer; equivalent to a one(1) horsepower motor;

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.