Suppose you have a simple circuit that includes a resistance device of 50 ohms, and the current flowing through it is 2.0 amps. solve for the potential difference of the batteries.

We can solve the problem by using Ohm's law, which can be written as:

where
is the potential difference across the resistor
I is the current flowing in the circuit
R is the resistance

In our circuit, I=2.0 A and the resistance is , so the potential difference across the batteries (equal to the potential difference of the battery) is

26.4 is about the right time