Physics, 27.08.2019 09:00 msdrake79

Models of four atoms are shown as figures a, b, c, and d. which two atoms represent isotopes of the same element?

Models of four atoms are shown as figures a, b, c, and d. which two atoms represent isotopes of the

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Answer from: AbhiramAkella

The identity of the element is determined by the number of protons
in the nucleus of each atom.

If two atoms have the same number of protons in their nucleii
(nucleuses) but different numbers of neutrons, then they're both
atoms of the same element, but their atomic masses are different,
and they're called isotopes of the element.

In the picture, atoms 'A' and 'B' each have 3 protons in the nucleus,
so they're both atoms of Lithium. But the number of neutrons is
different, so 'A' and 'B' are different isotopes of Lithium.

Also in the picture, atoms 'C' and 'D' each have 4 protons in the
nucleus, so they're both atoms of Beryllium. But the number of
neutrons is different, so 'C' and 'D' are different isotopes of Beryllium.

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..

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