Asatellite of mass 6500 kg orbits the earth in a circular orbit of radius of 7.5 106 m (this is above the earth's atmosphere).the mass of the earth is 6.0 1024 kg. what is the speed of the satellite?

The two forces, centripetal force and gravity are equal 

So, G M m / r^2 = (m V^2) / r 

so sqrt (GM/r)= V 

G is a gravitational constant which is G=6,67.10exp(-11) 

Sqrt (6.67 x 10^-11) (6 x 10^24)/7.5 x 10^6

so V= 7.30479295e9 or 7305 m/s 

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

b

explanation: