How many air molecules are in a 14.0×12.0×10.0 ft room? assume atmospheric pressure of 1.00 atm, a room temperature of 20.0 ∘c, and ideal behavior. volume conversion: there are 28.2 liters in one cubic foot?

There are 1.19.10²⁷ air molecules in the room

In general, the gas equation can be written

where

P = pressure, atm, N / m²

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K (P = atm, v = liter), or 8.314 J / mol K (P = Pa or N / m2, v = m³)

T = temperature, Kelvin

n = N / No

n = mole

No = Avogadro number (6.02.10²³)

n = m / m

m = mass

M = relative molecular mass

room volume: 14x12x10 = 1680 ft³

T = 20 °C = 20 +273 = 293 K

1 ft³ = 28.2 liters, then

1680 ft³ = 47376 liters

Which equation agrees with the ideal gas law  

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Which law relates to the ideal gas law  

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i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

real, smaller and upside-down.   so the answer should be b.