Aplane drops a package to some needy people in the jungle from a height of 1000m. how long will it take the package to strike the ground?

Hello!

Here we can use t=sqrt(2d/g)

So t=sqrt(2000m/9.80m/s^2)=14.3s

This came from the kinematic equation x2=x1+v1*t+1/2at^2

I rearranged for time and dropped the v1t term as there was no initial velocity.

Hope this helps. Any questions please feel free to ask. Thank you!!

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.