The force in newtons on a particle directed along the x-axis is given by f(x)=exp(−(x/2)+6) for x≥0 where x is in meters. the particle is constrained to move along the x-axis. find the work done in joules on the particle, w, in moving it from x=0 to x=1 using the fact that f=dw/dx. for your reference, 1 joule = 1 newton × 1 meter.,

To find the work done on the particle, the following is the solution:

Dw = F dx

W = integral over the path ( F(x) dx)

W = integral from 0 to 1 (e^(-x/5 + 5) dx)

W = -5e^(-x/5 + 5) from 0 to 1

W = 135 J

The work done is 135 J.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer