Fluorine is more electronegative than oxygen because 1. the outer orbitals of fluorine are located further from the nucleus than the outer orbitals of oxygen. 2. the effective nuclear charge of fluorine is greater than that of oxygen. 3. the effective nuclear charge of oxygen is greater than that of fluorine. 4. the outer orbitals of oxygen are located closer to the nucleus than the outer orbitals of fluorine. 5. false; oxygen is more electronegative than fluorine.

Fluorine and Oxygen are located in the same period of the periodic table, but different groups. This means that they both have the same number of electron shells, but the valence electrons are different. Fluorine has 7 valence electrons and Oxygen has 6 valence electrons.
Oxygen has 6 protons therefore has a nuclear charge of +6 and Fluorine has 7 protons so has a nuclear charge of +7. This shows that Fluorine has a higher nuclear charge than Oxygen therefore the attraction of the nucleus to valence electrons is higher in Fluorine than in Oxygen, as Fluorine has a higher nuclear charge than O.
the electrostatic attraction between nucleus and valence electrons of Fluorine is greater. Also higher the nuclear charge the more the pull is for the outer electrons so atomic radius decreases across the period. The size of Fluorine is smaller and charge is greater, the ratio of charge to size is greater in Fluorine that results in a strong pull of the valence electrons and even any electron that will be gained by Fluorine during bonding.

Correct response is 2. effective nuclear charge of Fluorine is greater than that of Oxygen

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