Idrop a penny from the top if tower at the front of fort collins high school and it takes 1.85 seconds to hit the ground calculate the velocity in m/s after 1.10 seconds of frefall and calculate the velocity at impact i'm mi/hr

Velocity after 1.10 s of free fall: vf = vi + at = 0 + (9.81 m/s^2)(1.10s) = 10.8 m/s velocity at impact: vf = vi + at = 0 + (9.81 m/s^2)(1.85s) = 18.1 m/s or (18.1 x 2.237) mi/hr = 40.5 mi/hr

When you go to ask a qustion there will be a picture of a paper clip looking thing and then it will pop up your files and you click on the imajes and then you up load it

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.