If a steel, thin-shelled wheel of radius r and mass m is moving along the road at 2 m/s, what is the total kinetic energy? 1) 2m 2) 3m 3) 1m 4) 5m 5) 4m

The moment of inertia for rolling motion is
I = Mr²

The linear velocity is v = 2 m/s. The rotational velocity is
ω = 2/r 

The total KE (kinetic energy) is
KE = (1/2)Mv² + (1/2) I ω²
     = (1/2)(M)(4) + (1/2)(Mr²)(4/r²)
    = 2M + 2M
    = 4M

  4M