How high a hill would a 75 kg hiker has to climb to increase her gravitational potential energy by 10000 j

Explanation:

Given that,

Mass of the hiker is 75 kg

The gravitational potential energy by 10000 J

To solve :

The height of the hill.

Solve :

The gravitational potential energy of object , .

Also, Mass of hiker,

Now,

The relation between Gravitational potential energy (G) and Mass of object (M) is given as:

Where , g is acceleration due to gravity, .

Putting , values of G, g and m in above equation.

We get,

Hence , this is the required solution.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft