Physics, 01.08.2019 20:00 amandasantiago2001

Two very large parallel sheets are 5.00 cm apart. sheet a carries a uniform surface charge density of -9.70 μc/m2 , and sheet b, which is to the right of a, carries a uniform charge of -11.5 μc/m2 . assume the sheets are large enough to be treated as infinite.

Answers: 1

Show answers

Answers

Answer from: timozy95

Question is missing. Found on internet the complete text of the problem:

"Two very large parallel sheets are 5.00 cm apart. Sheet A carries a uniform surface charge density of −9.70µC/m2, and sheet B, which is to the right or A, carries a uniform charge density of −11.5 µC/m2. Assume the sheets are large enough to be treated as infinite. Find the magnitude and direction of the net electric field these sheets produce at a point (a) 4.00 cm to the right of sheet A; (b) 4.00 cm to the left of sheet A; (c) 4.00 cm to the right of sheet B."

Solution:

(a) The electric field produced by a uniformly charged sheet at any distance is given by
$E= \frac{\sigma}{2 \epsilon _0}$
where $\sigma$ is the charge density and $\epsilon _0 = 8.85\cdot 10^{-12} F/m$ is the vacuum permittivity.

First of all, let's compute the fields generated by the two sheets separately. The two densities of charge are $\sigma_A = -9.70 \mu C/m^2=-9.70\cdot 10^{-6}C/m^2$ and $\sigma_B = -11.5 \mu C/m^2 = -11.5\cdot 10^{-6} C/m^2$ .

Sheet a gives an electric field of
$E_A= \frac{\sigma_A}{2\epsilon _0}= \frac{-9.7\cdot 10^{-6} C/m^2}{2\cdot 8.85\cdot 10^{-12} F/m} = -5.48\cdot 10^5 V/m$
where the negative sign means the field points towards sheet A, in any point of the space.

The electric field produced by sheet B is given by:
$E_B = \frac{\sigma_A}{2\epsilon _0}= \frac{-11.5\cdot 10^{-6} C/m^2} {2\cdot 8.85\cdot 10^{-12} F/m} =-6.50\cdot 10^{5} V/m$
and again, the negative sign means that the field at any point of the space points towards sheet B.

The point at which we have to compute the total field is at 4.00 cm right of sheet A. Since the two sheets are 5.00cm far apart, it means that this point is between the two sheets. Therefore, in this point the two fields point into opposite directions. Therefore, the total field is
$E=E_1-E_2= -5.48\cdot 10^5 V/m - (-6.50\cdot 10^{5} V/m)=1.02\cdot 10^5 V/m$
And the direction is towards sheet B, since it has a field with stronger intensity.

(b) Field at 4.00 cm to the left of sheet A: in this point of the space, the two fields point towards same direction (on the right, towards both sheet A and sheet B). So, the total field is simply the sum of the two fields:
$E=E_1+E_2=-11.98\cdot 10^5 V/m$
towards right.

(c) Field at 4.00 cm to the right of sheet B. As before, the two fields in this point have same direction (both towards left, pointing towards both sheet A and sheet B). And so, the total field is simply the sum of the two fields:
$E=E_1+E_2=11.98 \cdot 10^5 V/m$
towards left.

Answer from: Quest

cant without the picture! ?

Answer from: Quest

Iknow the first part it is the average star i am not 100% sure

Another question on Physics

Physics, 21.06.2019 16:20

Luke and carrie are driving down a straight section of the interstate at 70 mph in luke's new convertible. carrie is drinking a soda in the passenger seat. when she is done she tosses the bottle straight up in the air, just above the height of the car. what will happen to the bottle if air resistance is neglected? a. the bottle will land in carrie's lap. b. not enough information is given. c. the bottle will land on the interstate in front of the car. d. the bottle will land on the interstate behind the car.

Answers: 1

Answer

Physics, 22.06.2019 12:10

Two forces produce equal torques on a door about the door hinge. the first force is applied at the midpoint of the door; the second force is applied at the doorknob. both forces are applied perpendicular to the door. which force has a greater magnitude?

Answers: 2

Answer

Physics, 22.06.2019 19:30

Acamcorder has a power rating of 20 watts. if the output voltage from its battery is 9 volts, what current does it use?

Answers: 2

Answer

Physics, 22.06.2019 23:00

Hunter’s velocity was 4.5 m/s. at the end of his race, his velocity was the same. which best describes his movement? his movement stopped. his acceleration is zero. his time was constant. his acceleration was positive.

Answers: 1

Answer

You know the right answer?

Two very large parallel sheets are 5.00 cm apart. sheet a carries a uniform surface charge density o...

Questions