What charge is stored in a 180uf capacitor when 120v is applied to it?

Q = C*V
Q is the charge in coulombs.
C is the capacitance in Farads
V is the voltage in volts.

Q = ???
C = 180 * 10^-6 F
V = 120 V (I'm assuming DC here. If that's wrong, edit the question and offer more information. The next step is Calculus and if that's what you need, please say so.)

Q = C*V
Q =180 * 10^-6 * 120
Q = 0.0216 Coulombs. 

Distance^2= yellow line ^2 (see picture) = 30^2 + 49^2so distance = squareroot of (300^2 +49^2)i dont know if this is how to solve it, but i cnt think of another way

Biased means unfair but that's all ik