If 56 grams of carbon monoxide burns in oxygen to produce 88 grams of carbon dioxide, the mass of oxygen involved in the reaction grams. 32 56 88 144

Answer : The mass of oxygen involved in the reaction is, 32 grams.

Explanation : Given,

Mass of carbon monoxide = 56 g

Mass of carbon dioxide = 88 g

Molar mass of carbon monoxide = 28 g/mole

Molar mass of oxygen = 32 g/mole

First we have to calculate the moles of carbon monoxide.

Now we have to calculate the moles of oxygen gas.

The balanced chemical reaction will be,

From the balanced chemical reaction, we conclude that

2 moles of CO react with 1 mole of

So, the moles of = 1 mole

Now we have to calculate the mass of oxygen.

Therefore, the mass of oxygen involved in the reaction is, 32 grams.

are you like autistic or something?

xd

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day