Abullet is fired through a board, 14.0 cm thick, with its line of motion perpendicular to the face of the board. if it enters with a speed of 450 m/s and emerges with a speed of 220 m/s, what is the bullet's acceleration as it passes through the board?

The acceleration of a bullet that is fired through a board of 14.0 cm thick, with an initial and final speed of 450 m/s and 220 m/s, respectively, is -5.50x10⁵ m/s².  

The acceleration of the bullet can be calculated with the following equation:

  (1)

Where:

: is the final speed = 220 m/s

: is the initial speed = 450 m/s

a: is the acceleration =?

d: is the distance = 14.0 cm = 0.14 m

Hence, by solving equation (1) for a, we have:

The minus sign is because the bullet decelerates as it passes through the board.  

Therefore, the bullet's acceleration as it passes through the board is -5.50x10⁵ m/s².

To learn more about negative acceleration, go here: link

I hope it helps you!  

Explanation:

Here we know

initial speed will be

final speed is

total distance moved through it is given as

now we will use kinematics to find the acceleration

the force required to move the cart is divided by three or 33.33 n.