Three people pull simultaneously on a stubborn donkey. jack pulls eastward with a force of 92.5 n, jill pulls with 89.9 n in the northeast direction, and jane pulls to the southeast with 163 n. (since the donkey is involved with such uncoordinated people, who can blame it for being stubborn? ) find the magnitude of the net force the people exert on the donkey.

Jack force of 92.5 n   eastwardFjack(X)=92.5 n   Fjack(Y)=0

jill force of 89.9 n   northeast
Fjill(X)=cos45*89.9=63.57 n
Fjill(Y)=sin45*89.9=63.57 n

jane force of 163 n   southeast
Fjane(X)=cos45*163=115.26 n
Fjane(X)=-sin45*163=-115.26 n

Ftotal (X)=92.5+63.57+115.26=271.33 n
Ftotal (Y)=0+63.57-115.26=-51.69 n

Fotal=((271.33)^2+(-115.26)^2) ^0.5=294.80 n southeast

the magnitude of the net force the people exert on the donkey. is 294.80 n southeast

Iwannasay c is the most accurate